(1/3)|x-1| - |3x+1-3| = 3x-1.
√6x+1 + √4x+2 = √8x + √2x+3.
|x|log|y| = 4
x·y = 40.
a + b + c + d=7Uputa: a3+b3+c3+d3=3abc+3abd+3acd+3bcd+ (a+b+c+d)(a2+b2+c2+d2-ab-ac-ad-bc-bd-cd).
a2 + b2 + c2 + d2=15
a3 + b3 + c3 + d3=37
1/a + 1/b + 1/c + 1/d = 17/6.
x√9 - 9 · x√3 = 10.
|x + |x + |x+1| | | = 1/3.
|x2+3x+2| + |2x+3-x2| = 14.
log2 x + log3 x = log4 x + 1.
log2 (x + log3 2x) = 0,koliko je 6x?
(Ovaj zadatak je izvorno imao grešku. Priznavat će se približno rješenje onima koji su riješili prethodnu verziju zadatka.)
a x2 - x + a ≥ 0.
(m+1)x2 + m2-2m > 0.
xx ≥ x2.
∛x+5 + ∛2(x+4) ≤ ∛3x+13.
3 √2-x + x < 4.
0.301 < log 2 < 0.302, te0.476 < log 3 < 0.478.
4(|x+1|-2) > |x-1|.
log1/3 |x2-4x|+3 > 0. x2+|x-5|
log2 (log1/2 x+1 ) ≤ 1. x-1